taskwarrior/test/tree.t.cpp
2010-12-28 21:17:23 +01:00

82 lines
2.2 KiB
C++

////////////////////////////////////////////////////////////////////////////////
// taskwarrior - a command line task list manager.
//
// Copyright 2006 - 2010, Paul Beckingham, Federico Hernandez.
// All rights reserved.
//
// This program is free software; you can redistribute it and/or modify it under
// the terms of the GNU General Public License as published by the Free Software
// Foundation; either version 2 of the License, or (at your option) any later
// version.
//
// This program is distributed in the hope that it will be useful, but WITHOUT
// ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS
// FOR A PARTICULAR PURPOSE. See the GNU General Public License for more
// details.
//
// You should have received a copy of the GNU General Public License along with
// this program; if not, write to the
//
// Free Software Foundation, Inc.,
// 51 Franklin Street, Fifth Floor,
// Boston, MA
// 02110-1301
// USA
//
////////////////////////////////////////////////////////////////////////////////
#include "Context.h"
#include "Tree.h"
#include "test.h"
Context context;
////////////////////////////////////////////////////////////////////////////////
int main (int argc, char** argv)
{
UnitTest ut (8);
// Construct tree as shown above.
Tree t ("");
Tree* b = new Tree ("");
b->attribute ("name", "c1");
b->tag ("tag");
t.addBranch (b);
b = new Tree ("");
b->attribute ("name", "c2");
t.addBranch (b);
b = new Tree ("");
b->attribute ("name", "c3");
t.addBranch (b);
Tree* l = new Tree ("");
l->attribute ("name", "c4");
b->addBranch (l);
// Iterate over tree.
std::vector <Tree*> all;
t.enumerate (all);
ut.is (all[0]->attribute ("name"), "c1", "c1");
ut.is (all[1]->attribute ("name"), "c2", "c2");
ut.is (all[2]->attribute ("name"), "c4", "c4");
ut.is (all[3]->attribute ("name"), "c3", "c3");
all[3]->tag ("one");
all[3]->tag ("two");
ut.ok (all[3]->hasTag ("one"), "hasTag +");
ut.notok (all[3]->hasTag ("three"), "hasTag -");
ut.is (t.count (), 5, "t.count");
all.clear ();
b->enumerate (all);
ut.is (all[0]->attribute ("name"), "c4", "t -> c3 -> c4");
return 0;
}
////////////////////////////////////////////////////////////////////////////////